60-7w^2=0

Solution for 60-7w^2=0 equation:

60-7w^2=0

a = -7; b = 0; c = +60;
Δ = b2-4ac
Δ = 02-4·(-7)·60
Δ = 1680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1680}=\sqrt{16*105}=\sqrt{16}*\sqrt{105}=4\sqrt{105}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{105}}{2*-7}=\frac{0-4\sqrt{105}}{-14}
=-\frac{4\sqrt{105}}{-14}
=-\frac{2\sqrt{105}}{-7}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{105}}{2*-7}=\frac{0+4\sqrt{105}}{-14}
=\frac{4\sqrt{105}}{-14}
=\frac{2\sqrt{105}}{-7}
$